Welcome Guest ( Log In | Register ) Pi of the Bible and 9!, Nine Factorial Options P JayS Oct 01, 2012, 05:39 AM Post #1 Demi-God     Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 x^4 / x^3 = 1/1 = 3/3 = 81/27 = 3 = xx^3 + x^2 + x = 39 + x^4 = 120x + 1 = 4x^2 + 1 = 10 x^3 + 1 = 28 which is 4 * 7^139 + 1 = 40 which is 4 * 10120x = 360 which is pi=3120 + 1 = 11^2 = (x^2 + 2)^236x / x^4 = 36 x=136x / x^4 = 1.333... x=336x / x^4 = P/10 x=7^140 * 7^7 = 3294172032941720 * P/10 = 3457440 which is the perimeter of the circumference and the concentric square and the inscribed hexagon labelled (per).9! / (P/10) = 3457440 / 6 = 576240 radius2r * 3 = 3457440 Pi = 3The Molten Sea mentioned in the Bible had a radius of 5 cubits. The circumference was 6 times the radius around = 30 cubits. This resulted in a diameter of 10 cubits and a pi of 30/10= 3.This is based on a circle and hexagon with a perimeter of 3457440 / 6 = 576240 radius.3457440 / 2r = 3At this time 10 is not used. P/10 is not P. I simply label the decimal P/10 that occurs naturally from 252 / 2401.i don't think that P was invented with 9!. Therefore a circle was C = 3d not C = 3dP.P/10 * 10 = PThis brings 10 into the count and makes 10! instead of 9!.3457440 * P = 10!3457440 / P = 4 * 7^710! therfore equals 4 * 7^7 * P^210! / 3P = 2r = 1152480 / 2 = 576240 radius. The same radius as 9!.In 2D (two dimensions) the arc of the circle is longer than the radius of the subtended line. The arc = r * P = 0.5 * P = pi / 6 = 0.524781341... 6r = the perimeter of the inscribed hexagon6r * P = the circumference of the circle at 10! using base 10.120 * pi=3 = 360360 / (P/10) = 34303430 / 7^3 = 10 360 / 7^3 = P in base 10.   P JayS Dec 31, 2012, 04:33 AM Post #2 Demi-God     Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 x^4 + x^3 = 108108 / x = 3636 x / x^4 = 36 then x = 136 x / x^4 = P/10 then x = 79! / (P/10) = 3457440 which is the perimeter of the inscribed hexagon from the Creative Pi Geometric Spencer Construction.3457440 / 6 = the side of the radius = 5762402 times the radius = 1152380 which is the diameter.3457440 / 1152480 = 3 the perimeter of the inscrbed hexagon divide the diameter = a pi of 3.All that is proved is that the perimeter of the inscribed hexagon is 3 when the diameter is 1.However P/10 times 10 = P3457440 * P = 10! 10! makes a perfect circumference.C / d = 3PC = 3dP36x / x^4 = P/1010(36x) / x^4 = Px = 72520 / 2401 = PP = zC = (x y^7 z^2) = 10!, x=4, y=7 and z=360/7^3C / z = the perimeter of the inscribed hexagon = 3457440divide 3 = the diameter 1152480divide 2 = the radius 576240Pi = 3628800 / 1152480 = 1080 / 7^3 = 3P which is Creative Pi or rational pi.P = The arc of the circle which subtends the radius is longer than the radius.r = 1P = 360/7^33P = pi circumference = 1080 / 7^3   1 User(s) are reading this topic (1 Guests and 0 Anonymous Users)
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